I need to use the fact that $\tan 2x=\sin2x \ /\cos2x$ to prove that $$\tan 2x=\frac{2\tan x}{1\tan^2x}$$ I don't know where to start Please help or hint Thanks in advance Transcript Example 28 If tan𝑥 = 3/4 , "π" < 𝑥 < 3𝜋/4 , find the value of sin 𝑥/2 , cos 𝑥/2 and tan 𝑥/2 Given that "π" < x < 3𝜋/2 ie180° < x < 3/2 × 180° ie 180° < x < 270° Dividing by 2 all sides (180°)/2 < 𝑥/2 < (270°)/2 90° < 𝑥/2 < 135° So, 𝑥/2 lies in 2nd quadrant In 2nd quadrant, sin isPerform the addition or subtraction tanx sec^2x/tanx tan^2(x)/tan(x) sec^2x/tanx = tan^2x sec^2x / tanx then I use the identity 1tan^2u=sec^2u I do not know what to do at this point Mathematics Trigonometric Identities
Tanx 4 3 X In Quadrant Ii Find The Value Of Sinx 2 Cosx 2 Tanx 2
